Python 使用互斥量来处理资源分配

import threading
import time
 
num = 0
def count_test1():
global num
for i in range(100000):
mutex.acquire()
num += 1
mutex.release()
print("count_test1-->num:%s"%num)
 
def count_test2():
global num
for i in range(100000):
mutex.acquire()
num += 1
mutex.release()
print("count_test2-->num:%s"%num)
 
mutex = threading.Lock()
t1 = threading.Thread(target=count_test1)
t2 = threading.Thread(target=count_test2)
 
t1.start()
t2.start()
 
t1.join()
t2.join()
 
print("最终的num:%s"%num)